Category >
CSHARP
|| Published on :
Monday, March 13, 2023 || Views:
150
||
C# JSON Newtonsoft.Json data interchange deserialization
In this article, we will discuss how to convert a JSON string to an object in C# using the Newtonsoft.Json library. We will cover the basics of JSON and demonstrate step-by-step how to deserialize a JSON string into a C# object.
JSON (JavaScript Object Notation) is a widely used data format for exchanging data between client and server applications. It is lightweight, easy to read and write, and supports a variety of data types. In this article, we will discuss how to convert a JSON string to an object in C#.
What is JSON?
JSON is a lightweight data interchange format that is easy to read and write for humans and machines alike. It is based on a subset of the JavaScript programming language and is commonly used for web applications. JSON data is represented as key-value pairs, similar to a dictionary in Python.
Converting JSON String to Object in C#
Converting a JSON string to an object in C# is a simple process. First, we need to deserialize the JSON string into an object using the Newtonsoft.Json library.
Here is an example of how to convert a JSON string to an object in C#:
using Newtonsoft.Json;
string json = "{\"name\":\"John\",\"age\":30,\"city\":\"New York\"}";
Person person = JsonConvert.DeserializeObject<Person>(json);
Console.WriteLine(person.name);
Console.WriteLine(person.age);
Console.WriteLine(person.city);
public class Person
{
public string name { get; set; }
public int age { get; set; }
public string city { get; set; }
}
In the above code, we first create a JSON string with some sample data. We then use the JsonConvert.DeserializeObject method to deserialize the JSON string into a Person object. Finally, we access the properties of the Person object using the dot notation.
Conclusion
In conclusion, converting a JSON string to an object in C# is a simple process using the Newtonsoft.Json library. By using this library, we can easily convert JSON data to C# objects and vice versa.